# Proof 0 = 1
This is a meme:
Start with the assumption:
$a=b$
Mulitply each side by $a$ and subtract by $b^2$
$a^2-b^2=ab-b^2$
Factor out the $a-b$ term:
$(a-b)(a+b)=(a-b)(b)$
Divide by $(a-b)$
$a+b=b$
Substitute the original assumption: $a=b$
$b+b=b$
Divide by $b$ and subtract 1 from each side:
$1=0$
# Proof 0.999 = 1
For the sake of brevity, anytime 0.999 is written, in implies it repeats for infinity.
Set the variable:
$x=0.999$
Multiply both sides by 10:
$10x=9.999$
Subtract $x$ from each side;
$9x=9.999 - x$
Replace the $x$ on the right hand side with the definition from above:
$9x=9.999 -0.999=9$
Divide each side by 9:
$x=1$
Therefore:
$0.999=1$
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